integer to String :
int i = 42; String str = Integer.toString(i);
or
String str = "" + i
double to String :
String str = Double.toString(i);
long to String :
String str = Long.toString(l);
float to String :
String str = Float.toString(f);
String to integer :
str = "25"; int i = Integer.valueOf(str).intValue();
or
int i = Integer.parseInt(str);
String to double :
double d = Double.valueOf(str).doubleValue();
String to long :
long l = Long.valueOf(str).longValue();
or
long l = Long.parseLong(str);
String to float :
float f = Float.valueOf(str).floatValue();
decimal to binary :
int i = 42; String binstr = Integer.toBinaryString(i);
decimal to hexadecimal :
int i = 42; String hexstr = Integer.toString(i, 16);
or
String hexstr = Integer.toHexString(i);
hexadecimal (String) to integer :
int i = Integer.valueOf("B8DA3", 16).intValue();
or
int i = Integer.parseInt("B8DA3", 16);
ASCII code to String :
int i = 64; String aChar = new Character((char)i).toString();
integer to ASCII code (byte) :
char c = 'A'; int i = (int) c; // i will have the value 65 decimal
To extract Ascii codes from a String :
String test = "ABCD"; for ( int i = 0; i < test.length(); ++i ) { char c = test.charAt( i ); int i = (int) c; System.out.println(i); }
integer to boolean :
b = (i != 0);
boolean to integer :
i = (b)?1:0;
note :To catch illegal number conversion, try using the try/catch mechanism.
try{ i = Integer.parseInt(aString); } catch(NumberFormatException e) { }
